(10x+1)(2x^2-4x+1)=0

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Solution for (10x+1)(2x^2-4x+1)=0 equation: 


Simplifying
(10x + 1)(2x2 + -4x + 1) = 0

Reorder the terms:
(1 + 10x)(2x2 + -4x + 1) = 0

Reorder the terms:
(1 + 10x)(1 + -4x + 2x2) = 0

Multiply (1 + 10x) * (1 + -4x + 2x2)
(1(1 + -4x + 2x2) + 10x * (1 + -4x + 2x2)) = 0
((1 * 1 + -4x * 1 + 2x2 * 1) + 10x * (1 + -4x + 2x2)) = 0
((1 + -4x + 2x2) + 10x * (1 + -4x + 2x2)) = 0
(1 + -4x + 2x2 + (1 * 10x + -4x * 10x + 2x2 * 10x)) = 0
(1 + -4x + 2x2 + (10x + -40x2 + 20x3)) = 0

Reorder the terms:
(1 + -4x + 10x + 2x2 + -40x2 + 20x3) = 0

Combine like terms: -4x + 10x = 6x
(1 + 6x + 2x2 + -40x2 + 20x3) = 0

Combine like terms: 2x2 + -40x2 = -38x2
(1 + 6x + -38x2 + 20x3) = 0

Solving
1 + 6x + -38x2 + 20x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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